Question 782261
Assuming order doesn't matter, then...



n C r = (n!)/(r!(n-r)!)


24 C 4 = (24!)/(4!*(24-4)!)


24 C 4 = (24!)/(4!*20!)


24 C 4 = (24*23*22*21*20!)/(4!*20!)


24 C 4 = (24*23*22*21)/(4!)


24 C 4 = (24*23*22*21)/(4*3*2*1)


24 C 4 = (255024)/(24)


24 C 4 = 10626



Assuming order doesn't matter, then there are <font color="red">10626</font> different groups.