Question 782251


{{{(x+5)^2=14}}} Start with the given equation.



{{{x+5=""+-sqrt(14)}}} Take the square root of both sides.



{{{x+5=sqrt(14)}}} or {{{x+5=-sqrt(14)}}} Break up the "plus/minus" to form two equations.



{{{x=-5+sqrt(14)}}} or {{{x=-5-sqrt(14)}}} Subtract {{{5}}} from both sides.



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Answer:



So the solutions are {{{x=-5+sqrt(14)}}} or {{{x=-5-sqrt(14)}}}.