Question 66971
When the binomial (2x-3y)^11 is expanded, what is the coefficient of x^8y^^3 taking into consideration the coefficients 2 and -3. Thank you
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=[11C8](2x)^8(-3y)^3
=165(256x^8)*(-27y^3)
=-1140480x^8y^3
The coefficient is -1140480
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Cheers,
Stan H.