Question 781633
We use the Standard Form:

{{{
y=a*(x-h)^2+k
}}}
from the vertex we get:
{{{
y=a*(x-3)^2-8
}}}

since the origin is on the graph, 

{{{
0=a*(0-3)^2-8
}}}


{{{9a=8}}}

{{{a=9/8}}}


so we can write
{{{
y=(9/8)*(x-3)^2-8
}}}