Question 66962
1+2i
----
2-3i
:
Multiply the equation by the conjugate of (2-3i) which is (2+3i)
:
{{{(1+2i)/(2-3i)}}} * {{{(2+3i)/(2+3i)}}} = {{{(2+7i+6i^2)/(4-9i^2)}}}
:
you should get it from here, remember i^2 = -1