<PRE><B>Question 780936</B>
 A goldsmith mixed 10 g of a 60% gold alloy with 40 g of a 25% gold alloy.
 What is the percent concentration of the resulting alloy? 
:
A typical mixture equation, the total result will be 10+40 = 50 mg
let x = the decimal form of resulting percent
:
.60(10) + .25(40) = 50x
6 + 10 = 50x
16 = 50x
16/50 = x 
x = .32, result is 32% gold alloy</PRE>