Question 781206
A box contains 3 red balls and 4 green balls. If two balls are randomly selected in sequence, what is the possibility that a red ball and a green ball are picked out of the box.
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# of ways to succeed: 3*4 = 12 pairs of red/green
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# of possible pairs:: 7C2 = 21
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P(red/gree pair) = 12/21 = 4/7
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Cheers,
Stan H.