Question 780966
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A number:  *[tex \LARGE x]


6 times a number:  *[tex \LARGE 6x]


4 more than 6 times a number:  *[tex \LARGE 6x\ +\ 4]


is:  *[tex \LARGE =]


-8:  *[tex \LARGE -8]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 6x\ +\ 4\ =\ -8]


Add -4 to both sides


Multiply both sides by *[tex \LARGE \frac{1}{6}]


Substitute your answer for *[tex \LARGE x] in *[tex \LARGE 6x\ +\ 4\ =\ -8] and do the arithmetic to check your work.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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