Question 780850
remember that a*log(b) = {{{log((b^a))}}}<P>log(x) <P>
log(x) = 2/3 * log(y) = log(y^(2/3)).  <P>
Remember if log(a) = log(b) then a=b<P>
x = y^(2/3)<P>
Similarly x = z^(2/5)<P>
y^(2/3) * y^(1/3) = y.  y^(1/3) = sqrt(x) so y = x*sqrt(x)<P>
z^(2/5) * z^(2/5) * z^(1/5) = z.  z^(2/5) = x, so that's x*x*sqrt(x) = x^2 * sqrt(x).<P>
yz = {{{x*sqrt(x) * x^2 * sqrt(x) = x^4}}}