Question 780820
Call x the amount invested at 3% and y at 2%.  Then x+y = 5500.<P>
The amount of interest earned for each investment is the amount invested times the interest rate.  For x it's .03x and for y it's .02y, and their sum must be greater than or equal to $135.<P>
.03x +.02y >= 135.<P>
Solve the first equation for x:  x = 5500-y.  Substitute that into the second equation.<O>
.03(5500-y) +.02y >= 135<P>
165 - .03y + .02y >= 135<P>
-.01y >= -30<P>
y <= 3000<P>
Check it:  3000*.02 + 2500*.03 = 60 + 75 = 135.  The most he can invest at 2% is $3000.