Question 780142
Given the functions
f(x)=1/(x+6) ; g(x)=x/(2-x) 
a.(f ∘ g)(-2) = f[g(-2)] = f[1/2] = 2/13
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b.(g ∘ f)(-2) = g[f(-2)] = g[1/4] = 7/4
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c.(f ∘ g)(x) = f[g(x)] = f[x/(2-x)] = 1/[x/(2-x) + 6] = x/(x+12-6x) = x/(12-5x)
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etc...
Cheers,
Stan H.
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d.(g ∘ f)(x)
e.(g ∘ g)(x)
f.(g ∘ g)(-2/3)