Question 779710
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Put it into standard form:


Distribute the *[tex \LARGE t] in the LHS, add *[tex \LARGE -3t^2\ -\ 6] to both sides, collect like terms, and multiply both sides by -1 to get:


*[tex \LARGE \ \ \ \ \ \ \ \ \ 2x^2\ -\ 3t\ +\ 6\ =\ 0]


Does not factor.  Use the quadratic formula.  Note:  *[tex \LARGE 9\ -\ 48\ <\ 0] hence you have a conjugate pair of complex roots.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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