<PRE><B>Question 779716</B>
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Just factor *[tex \LARGE 6x^3\ +\ 9x^2\ -\ 6] into three factors.  There are three different but all perfectly acceptable answers to the question posed depending on which of the three factors retains the common factor of 3.


Hint: Take out either *[tex \LARGE 3x^2] or *[tex \LARGE x^2] to start, and then factor the resulting quadratic.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
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My calculator said it, I believe it, that settles it
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