Question 779236
{{{ 3x^2 - 8x + 8 = 0 }}}
Use the quadratic formula
{{{ x = (-b +- sqrt( b^2 - 4*a*c )) / (2*a) }}}
{{{ a = 3 }}}
{{{ b = -8 }}}
{{{ c = 8 }}}
{{{ x = (-(-8) +- sqrt( (-8)^2 - 4*3*8 )) / (2*3) }}}
{{{ x = ( 8 +- sqrt( 64 - 96 )) / 6 }}}
{{{ x = ( 8 +- sqrt( -32 )) / 6 }}}
There is no solution because you are taking the square root of a
negative number which means you end up with two
imaginary roots that look like:
{{{ a + b*i }}} and {{{ a - b*i }}} where {{{ i = sqrt(-1) }}}
so there are no real solutions