Question 779196
The tens digit of a two-digit number is four times the units digit. If the digits are reversed, the sum of the new number and the original number is 110. What is the number?
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Let the number be 10t+u; its reverse is 10u+t
Equations:
t = 4u
10u+t + 10t+u = 110
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Substitute for "t" and solve for "u":
10u + 4u + 10*4u+u = 110
55u = 110
u = 2
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t = 4u = 8
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Original Number: 10t+u = 82
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Cheers,
Stan H.
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