Question 8588
I'm not sure, is this what you mean for the problem?


{{{ (7-4(3-6)^2)/(abs(3-12) )}}}


If this is it, then you must do the parentheses first:  (3-6) = -3 and within the absolute value, (3-12) = -9.


{{{ (7-4(-3)^2)/(abs(-9) )}}}


Next, do {{{(-3)^2=9}}} and {{{abs(-9) = 9}}}


{{{ (7-4*9)/9 }}}


Next, multiply 4*9=36


{{{ (7-36)/9}}}
{{{-29/9}}}


Does that look right?


R^2 at SCC