<PRE><B>Question 778769</B>
A cheetah is running at 65 mph an a gazelle is running at 47 mph. The cheetah is one mile behind the gazelle. Write an expression for the distance the cheetah must run to catch up with the gazelle
--------------------------
Gazelle DATA:
distance = x miles ; rate = 47 mph ; time = d/r = x/47 hrs.
--------------
Cheetah DATA:
distance = x+1 mile ; rate = 65 mph ; time = d/r = (x+1)/65 hrs.
-----
Equation:
time = time
x/47 = (x+1)/65
65x = 47x + 47
8x = 47
x = 5.875 miles
Cheetah distance = x+1 = 6.875 miles
=======================================
Cheers,
Stan H.
=======================
</PRE>