Question 778759
Find the quotient
{{{((2x^3-128)/4x)/((x^2-16)/(8x^2))}}}
Invert the divisor and multiply
= {{{((2x^3-128)/4x)*(8x^2/(x^2-16))}}}
Then factor and cancel.
Can you do the rest?
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= {{{((2x^3-128))*(2x/(x^2-16))}}}
= {{{(2(x-4)*(x^2 + 4x + 16))*(2x/((x-4)*(x+4)))}}}
= {{{(2(x^2 + 4x + 16))*(2x/((x+4)))}}}
= {{{4x(x^2 + 4x + 16)/(x+4)}}}