Question 778638
<pre>
g(x) = 4(x + 2)<sup>5</sup>(x-3)<sup>3</sup> + 5(x-3)<sup>4</sup>(x+2)<sup>4</sup>

g(x) = (x+2)<sup>4</sup>(x-3)<sup>3</sup>[4(x+2)+5(x-3)]

g(x) = (x+2)<sup>4</sup>(x-3)<sup>3</sup>[4x+8+5x-15]

g(x) = (x+2)<sup>4</sup>(x-3)<sup>3</sup>[9x-7]

x+2=0
 x=-2 is a zero of mutipicity 4

x-3=0
 x-3 is a zero of mutipicity 3

9x-7=0
  9x=7
   x={{{7/9}}} is a zero of mutiplicity 1.

It has three zeros:  -2, 3 and {{{7/9}}}

Edwin</pre>