Question 778663
The A2Z Company produces cylindrical pipes. If the radius of a cylindrical pipe is increased by one half of the original, what will happen to the volume of the pipe?
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Original Volume: pi*r^2*h
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New volume: pi((3/2)r)^2*h = (9/4)pi*r^2*y
The volume is increased to nine fourths of the original.
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Cheers,
Stan H.