Question 778639
The {{{n}}}-th term for an A.P. series with first term {{{a}}} and common difference {{{d}}} is given by {{{t[n]=a+(n-1)d}}}.


Here, {{{a=-1/6}}}, {{{d = 1/12-(-1/6)=1/12+1/6=3/12=1/4}}}.
{{{t[10]=-1/6+(10-1)(1/4)}}}
{{{t[10]=-1/6+9/4=(-2+27)/12=25/12}}}