Question 778521


{{{125-x^3}}} Start with the given expression.



{{{(5)^3-(x)^3}}} Rewrite {{{125}}} as {{{(5)^3}}}. Rewrite {{{x^3}}} as {{{(x)^3}}}.



{{{(5-x)((5)^2+(5)(x)+(x)^2)}}} Now factor by using the difference of cubes formula. Remember the <a href="http://www.purplemath.com/modules/specfact2.htm">difference of cubes formula</a> is {{{A^3-B^3=(A-B)(A^2+AB+B^2)}}}



{{{(5-x)(25+5x+x^2)}}} Multiply


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Answer:

So {{{125-x^3}}} factors to {{{(5-x)(25+5x+x^2)}}}.


In other words, {{{125-x^3=(5-x)(25+5x+x^2)}}}