Question 778476
If the graph of y=(ax+b)/(x+c) has a horizontal asymptote y=2 and a vertical asymptote x=-3, then a+c=? 
a. -5
b. -1
c. 0
d. 1
e. 5
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To find the vertical asymptote, set denominator=0, then solve for x:
x+c=0
x=-c=-3 (vertical asymptote)
c=3
..
If degree of numerator=degree of denominator, as in this case:
Horizontal asymptote= quotient of lead coefficient of numerator divided by lead coefficient of denominator.
horizontal asymptote=a/1=2
a=2
a+c=5