Question 778429


{{{64x^3+27}}} Start with the given expression.



{{{(4x)^3+(3)^3}}} Rewrite {{{64x^3}}} as {{{(4x)^3}}}. Rewrite {{{27}}} as {{{(3)^3}}}.



{{{(4x+3)((4x)^2-(4x)(3)+(3)^2)}}} Now factor by using the sum of cubes formula. Remember the <a href="http://www.purplemath.com/modules/specfact2.htm">sum of cubes formula</a> is {{{A^3+B^3=(A+B)(A^2-AB+B^2)}}}



{{{(4x+3)(16x^2-12x+9)}}} Multiply


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Answer:


So {{{64x^3+27}}} factors to {{{(4x+3)(16x^2-12x+9)}}}.


In other words, {{{64x^3+27=(4x+3)(16x^2-12x+9)}}}