Question 778376
distance: √[(x2- x1)^2 + (y2- y1)^2]
= √[(-5 - 1)^2 + (-1 - 4)^2]
= √[( -6)^2 + (-5)^2)]
= √(36 + 25)
= √61

midpoint: (x1 + x2)/2, (y1 + y2)/2
= (1 + -5)/2 , (4 + -1)/2
= -4/2 , 3/2
= -2 , 3/2