Question 778331
First calculate the Z-score.


For 5 yrs age the Z-score is {{{Z = (x - mu)/sigma = (5 - 4)/1 = 1}}}
For 4 yrs age the Z-score is {{{Z = (x - mu)/sigma = (4 - 4)/1 = 0}}}


The probability that the age of children is less than 5 years is
{{{P(x<5) = P(Z<1) = 0.84134}}}


The probability that the age of children is less than 5 years is
{{{P(x<4) = P(Z<0) = 0.5}}}


Using Standard Normal Distribution table, probability that the age of children lie between 4 and 5 years is given by
{{{P(4<x<5) = 0.84134-0.5=0.34134}}}


Try the rest yourself. If you still need help then let me know.