Question 778318
The y-intercept is at x=0.  
{{{F(0)=(1)(-5)(2)^2=-5*4=highlight(-20)}}}


The x-intercepts are at {{{x=1}}},{{{x=2&1/2}}},{{{x=-2}}}.


{{{graph(380,380,-5,5,-22,22,(1-x)(2x-5)(x+2)^2)}}}