Question 66188
No!  I'm afraid you combined unlike terms!!  


You need to FACTOR the numerator and denominator, then reduce the fraction:
{{{(4x-28)/(5x-35) }}}
{{{(4(x-7))/(5(x-7)) }}}


Now, the (x-7) factors divide out, leaving the final answer ={{{4/5}}}.


R^2 at SCC