<PRE><B>Question 778222</B>
Keisha drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took 8 hours. When Keisha drove home, there was no traffic and the trip only took 6 hours. If her average rate was  16 miles per hour faster on the trip home, how far away does Keisha live from the mountains?

way up

distance from home = x
speed = y
time =8 hours

d=rt
x=8y
x-8y=0...............(1)


return
distance =x
speed = y+16
time = 6 hours

x=6(y+16)
x=6y+96
x-6y=96...............(2)
x		-8	y	=	0	.............1	
								
x		-6	y	=	96	.............2	
Eliminate	y							
multiply (1)by		6						
Multiply (2) by		8						
6	x		-48	y	=	0		
8	x		-48	y	=	768		
Add the two equations								
14	x				=	768		
/	14							
x	=	55						
plug value of			x	in (1)				
1	x		-8	y	=	0		
55			-8	y	=	0		
			-8	y	=	0		-55
			-8	y	=	-55		
				y	=	7	
x= 55 the distance from home	


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