Question 778173
what is the sqrt (Square Root) of 24 x squared y to the 3rd power 
√24x²y³ = sqrt[4x^2y^2]*sqrt[6y] = 2xy*sqrt(6y)
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My second question is what is 3/(4-√5) (the slash mark between 3 and 4 is a division sign).
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To rationalize the denomiinator, multiply numerator
and denominator by 4+sqrt(5)
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= [3(4+sqrt(5)]/[(4-sqrt(5))(4+sqrt(5))
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= [12+3sqrt(5)]/[16-5]
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= [12+3sqrt(5)]/11
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Cheers,
Stan H.
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