Question 778057
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The domain set for *[tex \LARGE h(x)\ =\ \frac{1}{x^2\  +\ 4t}] is 


*[tex \LARGE \{x\ \in\ \mathbb{R}, x\ \not =\ \pm2 \sqrt{ -t }\}] if *[tex \LARGE t\ <\ 0]

and


*[tex \LARGE \{x\ \in\ \mathbb{R}\}] if *[tex \LARGE t\ \geq\ 0]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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