Question 777603
{{{9^(m+3)=81}}}.......you can write {{{81}}} as {{{9^2}}}

{{{9^(m+3)=9^2}}}......here you have same bases, then  exponents are same too

{{{(m+3)=2}}}...solve for {{{m}}}

{{{m=2-3}}}

{{{m=-1}}}

check:

{{{9^(m+3)=81}}}=> {{{9^(-1+3)=81}}}=>{{{9^2=81}}}=>{{{81=81}}}