Question 777570
Find the exact value.	
Given that Tanx=8/7 with x in quadrant I, find sin 2x
tanx=sinx/cosx
hypotenuse of working right triangle=&#8730;(8^2+7^2)=&#8730;113
sinx=8/&#8730;113
cosx=7/&#8730;113
{{{sin 2(x)=2sin(x)cos(x)=2(8/sqrt(113))(7/sqrt(113))=112/113}}}