Question 66762
kindly show me the answer and solution to this problem.....divide 56 into two parts.
HENCE THEY ARE X AND 56-X SAY.

 If the larger number exceeds twice the smaller number by 5,
IF X IS LARGER NUMBER ,THEN SMALLER NUMBER=56-X
TWICE IT = 2(56-X)=112-2X...........5 MORE.....= 112-2X+5=117-2X
HENCE
X=117-2X
3X=117
X=39
 find the numbers....
THE NUMBERS ARE 39 AND 56-39=17
i hope that you can show me the step-by-step solution and the answer