<PRE><B>Question 777551</B>
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Put the equation into standard form:


*[tex \LARGE y\ =\ -36x^2\ +\ 2500]


Set *[tex \LARGE y\ =\ 0]


*[tex \LARGE -36x^2\ +\ 2500\ =\ 0]


So *[tex \LARGE a\ =\ -36], *[tex \LARGE b\ =\ 0], and *[tex \LARGE c\ =\ 2500]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ \frac{-b\ \pm\ \sqrt{b^2\ -\ 4ac}}{2a}]


Plug in the numbers and do the arithmetic.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
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