<PRE><B>Question 63303</B>
log5+log(4-2x)=log(x-1)


By the Law of Logarithms:
log 5(4-2x) = log (x-1)


5(4-2x) = (x-1)
20 - 10x = x-1


Add 10x to each side of the equation.  Also add +1 to each side:
21=11x


Divide both sides by 11:

x= {{{21/11}}}


The answer is valid, since it does not cause the log of a negative!!

R^2 at SCC</PRE>