Question 776905
3 years ago a father was 4 times as old as his daughter is now. The product of their ages is 430. Calculate their present ages.


Let daughter's, and father's current ages be D, and F, respectively


Then: F - 3 = 4D ----- F = 4D + 3 ----- eq (i)


Also FD = 430 ------ eq (ii)


D(4D + 3) = 430 ----- Substituting {{{4D + 3}}} for F in eq (ii)


{{{4D^2 + 3D - 430 = 0}}}


Solve this to get daughter's age. Then find father's: {{{430/D}}}


You should get:


Daughter's current age: {{{highlight_green(10)}}}


Father's current age: {{{highlight_green(43)}}}


You can do the check!! 


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