Question 66734
Find an equation of a line that is perpendicular to the line of 5x-4y=20.
I had to find the x and y intercepts.  I have x=5 and y=4.  My answer needs to be in y=mx+b form.
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Find the slope of the given line, as follows:
5x-4y=20
4y=5x-20
y=(5/4)x-5
The given line has a slope of 5/4
So the line perpendicular to it must have a slope of -4/5
Therefore the equation of a line perpendicular to the
given line would be y=(-4/5)x+b where b is any number you
wish to make it.
Cheers,
Stan H.