Question 776657
Sin is opposite over hypotenuse.  Call the opposite side 6 and the hyp 10.<P>
cos is adjacent over tangent.  If you know Pythagorean triples you know the adjacent side has to be 8.  Otherwise use the Pythagorean theorem: {{{a^2 + b^2 = c^2}}} where a and b are the legs and c is hypotenuse.<P>
{{{6^2 + b^2 = 10^2}}}<P>
{{{b^2 = 100 - 36 = 64}}}<P>
{{{b = sqrt(64) = 8}}}<P>
tan = sin/cos = opp/adj = 6/8 = 3/4 = .75