Question 776677
{{{7/4 + (2/3 )y^2 = (13/6)y}}}

LCM of the denominators is 12. so multiply equation by 12

{{{(7*12)/4 + (2*12)/3 )y^2 = (13*12)/6)y}}}


21+8y^2=26y

8y^2-26y+21=0

Find the roots of the equation by quadratic formula							
			iiiii				
a=	8	,	b=	-26	,	c=	21
							
b^2-4ac=	676	+	-672				
b^2-4ac=	4						
{{{	sqrt(	4	)=	2	}}}		
{{{y=(-b+-sqrt(b^2-4ac))/(2a)}}}							
{{{y1=(-b+sqrt(b^2-4ac))/(2a)}}}							
y1=(	26	+	2	)/	16		
y1=	1.75						
{{{y2=(-b-sqrt(b^2-4ac))/(2a)}}}							
y2=(	26	-2	) /	16			
y2=	1.50						

y= 1.75 & 1.50