Question 776551
solve 2<|x-1|<5
we have 2 cases to consider
2<|x-1|   and  |x-1|<5
(1) 2<|x-1|
 2 < x-1
 3 < x
 -2 > x-1
 -1 > x
so we have x>3 or x<-1
(2) |x-1|<5
 x -1 < 5
 x < 6
 x -1 > -5
 x > -4
so we have -4 < x < 6
now we need to look at where (1) and (2) overlap
  -4 < x < -1  as well as 3 < x < 6