Question 776418
solve each system by elimination. 
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X+y+2z=4
X+2y+z=4
3x-y+z=3
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Subtract 1st from 2nd:::
Subtract 3 times 1st from 3rd:::
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X+y+2z=4
0+y-z = 0
0-4y-5z=-9
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Add 4 times 2nd to 3rd:::
X+y+2z=4
0+y-z = 0
0+0-9z= -9
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Solve 3rd for "z":
z = 1
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Solve 2nd for "y":
y-1 = 0
y = 1
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Solve 1st for "x":
x + y + 2z = 4
x + 1 + 2 = 4
x = 1
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Solution:
x = 1 ; y = 1 ; z = 1
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Cheers,
Stan H.
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