Question 66680
Find the sum of: {{{(-1/5)+(2/5)+(-3/5)+(3/5)+(4/5)+1}}} Since the fractions are over a common denominator of 5, you can rewrite this as:
{{{((-1)+(2)+(-3)+(3)+(4))/5+1}}} Add the numerators.
{{{(5/5) + 1}}} = {{{1+1 = 2}}}