Question 776150
#2.
The difference of the first two is (3x-x).
Twice the last is 2*5x.
{{{(3x-x)=2*5x}}}
{{{2x=2*5x}}}
{{{x=5x}}}
{{{0=4x}}}
{{{x=0}}}


...Or did you mean this?
{{{3x-x=2(5x-3x)}}}, using "difference of the last two numbers".
{{{2x=2*2x}}}
{{{2x=4x}}}
{{{0=2x}}}
{{{x=0}}}


These numbers are not. This question #2 does not conform to the problem description of your numbers.