Question 776192
x1		y1	x2	y2				
0      		5  1/ 2	-3  1/ 2	0    				
								
slope m =		(y2-y1)/(x2-x1)						
(	0    	-	5 1/2	)/(	-3 1/2	-	0    	)
(	-5 1/2	/	-3 1/2	)  				
m=		1  4/ 7						 
The required line passes through both the points. So we select one point and plug it with the slope 								
Plug value of  the slope  and point			(	0    	,	11/2	) in	
Y	=	m	x	+	b			
5.50	=	11/7	*	0    	+	b		
5.50	=	0    	+	b				
b=	11/2	+	-0    					
b=	11/ 2							
So the equation  will be								
Y 	=	11/7	x	+	11/2			
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