Question 775984
Let n be the width of the rectangle. Then its length is given by (n + 12).
 
Thus, we can write for the perimeter.
68 = 2n + 2(n + 12)
 
Solve for n.
68 = 2n + 2(n + 12)
68 = 2n + 2n + 24
68 = 4n + 24
4n = 44
n = 11
 
Therefore, the rectangle has the dimensions 11 × 23.