<PRE><B>Question 66676</B>
Here is wonderful step-by-step help
:
{{{(-3a^2b)/(35a^5)}}} * {{{(14a^3b^2)/(-9b^4)}}}
:
a^2 cancels into 35a^5 leaving:
{{{(-3b)/(35a^3)}}} * {{{(14a^3b^2)/(-9b^4)}}}
:
a^3 cancels into a^3 leaving:
{{{(-3b)/(35)}}} * {{{(14b^2)/(-9b^4)}}}
:
b^2 cancels into b^4 leaving:
{{{(-3b)/(35)}}} * {{{(14)/(-9b^2)}}}
:
b cancels into b^2 leaving:
{{{(-3)/(35)}}} * {{{(14)/(-9b)}}}
:
-3 cancels into -9 leaving:
{{{(+1)/(35)}}} * {{{(14)/(+3b)}}}
:
7 goes into 35 and 14 leaving:
{{{(1)/(5)}}} * {{{(2)/(3b)}}} = {{{(2/(15b))}}}</PRE>