Question 775856
let the number of men be x

No of days taken = x

x men will do 1/x of the job in 1 day

x+10 men

number of days = x-8

(x-8)/(x-10)  of the job in 1 day

{{{(x-8)/(x+10) = 1/x}}}

x^2-8x=x+10

x^2-9x-10=0

x^2-10x+x-10=0
x(x-10)+1(x-10)=0

(x-10)(x+1)=0

x=10 OR -1
ignore negative

x=10====> number of men

m.ananth@hotmail.ca