Question 775855
A group of men can do a job in as many days as there are men in the group. If the number of men is increased by 10, the number of days to do the job will be decreased by 8. Find the number of men in the group.

let the number of men be x

No of days taken = x

x men will do 1/x of the job in 1 day

x+10 men

number of days = x-8

(x-8)/(x-10)  of the job in 1 day

{{{(x-8)/(x+10) = 1/x}}}

x^2-8x=x+10

x^2-9x-10=0

x^2-10x+x-10=0
x(x-10)+1(x-10)=0

(x-10)(x+1)=0

x=10 OR -1
ignore negative

x=10====> number of men

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