Question 775810
{{{xy - 5y = 1}}}

{{{y(x - 5) = 1}}}

{{{y = 1/(x - 5)}}}

Since dividing by zero is not allowed the next step is only legitimate when {{{x<> 5}}}.

so, {{{y = 1 / (x - 5)}}} is defined for all {{{x}}} except {{{x<>5}}}


Technically therefore the answer would be {{{yes}}},the equation defines {{{y}}} as a function of {{{x}}}, {{{y}}} can be isolated on one side of the equal sign.

domain:  function {{{is}}} a defined  over { {{{x}}}| {{{x}}} &#8712; {{{R}}} and {{{x<>5}}} }